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              $
         \item $\chi=-\frac{1}{V}\mu_0\frac{\partial^2 E}{\partial B^2}
               \Rightarrow$
-             only second term contributes to $\chi$!
+             only second term contributes to $\chi$!\\
              $\chi=-\frac{1}{V}\mu_0\frac{e^2}{4m}<\phi|(x^2+y^2)|\phi>$
        \item $<\phi|x^2|\phi>=<\phi|y^2|\phi>=\frac{1}{3}<\phi|r^2|\phi>$\\
              $\Rightarrow \chi=-\frac{1}{V}\mu_0\frac{e^2}{6m}