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authorhackbard <hackbard@sage.physik.uni-augsburg.de>
Wed, 23 Apr 2008 09:50:53 +0000 (11:50 +0200)
committerhackbard <hackbard@sage.physik.uni-augsburg.de>
Wed, 23 Apr 2008 09:50:53 +0000 (11:50 +0200)
solid_state_physics/tutorial/2_01s.tex

index a89285334154eae2075e616659fcb51e12e032eb..5e23232119761f750cf514cd2a41e1f4b2018b3d 100644 (file)
              $
         \item $\chi=-\frac{1}{V}\mu_0\frac{\partial^2 E}{\partial B^2}
               \Rightarrow$
-             only second term contributes to $\chi$!
+             only second term contributes to $\chi$!\\
              $\chi=-\frac{1}{V}\mu_0\frac{e^2}{4m}<\phi|(x^2+y^2)|\phi>$
        \item $<\phi|x^2|\phi>=<\phi|y^2|\phi>=\frac{1}{3}<\phi|r^2|\phi>$\\
              $\Rightarrow \chi=-\frac{1}{V}\mu_0\frac{e^2}{6m}