-indicating structural identity (isomorphism) of $V$ and $V^{\dagger}$.
+The kernel is $\vec{v}=0$, structural identity (isomorphism) of $V$ and $V^{\dagger}$ is .
In physics and matrix algebra, the inner product is often defined with linearity in the second argument and conjugate linearity in the first argument.
This allows to express the inner product $(\vec{u},\vec{v})$ as a product of vector $\vec{v}$ with a dual vector or linear functional of dual space $V^{\dagger}$
In physics and matrix algebra, the inner product is often defined with linearity in the second argument and conjugate linearity in the first argument.
This allows to express the inner product $(\vec{u},\vec{v})$ as a product of vector $\vec{v}$ with a dual vector or linear functional of dual space $V^{\dagger}$
@@ -104,7+110,7 @@ or the conjugate transpose in matrix formalism