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+\begin{document}
+
+% header
+\begin{center}
+ {\LARGE {\bf Materials Physics II}\\}
+ \vspace{8pt}
+ Prof. B. Stritzker\\
+ SS 2008\\
+ \vspace{8pt}
+ {\Large\bf Tutorial 1}
+\end{center}
+
+\section{Diamagnetism}
+There is a linear relationship of the magnetic field ${\bf B}$ and
+the magnetization ${\bf M}$ of some material.
+The factor of proportionality is called the magnetic suscebtibility $\chi$.
+\[
+ \chi=\frac{\mu_0 {\bf M}}{{\bf B}}
+\]
+For negative values of $\chi$ the induced magnetization aligns opposite
+to the applied magnetic field.
+This behaviour is called diamagnetism.
+\\\\
+Develop an expression for the diamagnetic contribution to $\chi$ for some
+atom or ion.
+
+\begin{enumerate}
+ \item {\bf Classical approach:}\\
+ Consider the outer electrons of an atom or ion orbiting
+ the core with a radius $r$.
+ Apply a magnetic field $B$ perpendicular to the orbit plane.
+ According to Lenz's law the induced current creates a magnetic
+ field that tends to keep the magnetic flux unchanged.
+ \begin{enumerate}
+ \item Calculate the induced voltage $U$ due to the change in flux.
+ What is the related electric field $E$ along the orbit track?
+ Calculate the corresponding change of the electron velocity
+ due to the change of the magnetic field.
+ What is the resulting angular frequency $\omega_L$
+ (Larmor frequency, named after Joseph Larmor)?
+ \item Determine the magnetic momentum $\mu$ caused by the
+ Larmor precession of $Z$ electrons which have a mean square
+ distance $<r^2>$ to the core.
+ {\bf Hint:}
+ The magnetic momentum of a current loop is the product of
+ the current and the area of the loop.
+ The average square of the loop radius $<\rho^2>$ is the average
+ square distance of the electrons perpendicular to the direction
+ of the applied magnetic field ($<\rho^2>=<x^2>+<y^2>$).
+ The average square distance of the electrons to the core is
+ $<r^2>=<x^2>+<y^2>+<z^2>$.
+ Assuming a spherically symmetric charge distribution
+ the equality $<x^2>=<y^2>=<z^2>$ holds.
+ \item Write down the magnetic suscebtibility $\chi$.
+ {\bf Hint:} By definition the magnetization is given by $N\mu$,
+ where $N$ is the amount of atoms per unit volume.
+ \end{enumerate}
+ \item {\bf Quantum mechanical theory:}\\
+ In the presence of a magnetic field ${\bf B}=\nabla\times{\bf A}$
+ the kinetic part of the Hamiltonian is extended to read
+ \[
+ H_{kin}=\frac{1}{2m}(-i\hbar\nabla_{r}-e{\bf A})^2
+ =H_{kin}^0 + H_{kin}'
+ \]
+ where ${\bf A}$ is the vector potential and $H_{kin}^0$ is
+ the kinetic part of the Hamiltonian without apllied magnetic field.
+ \begin{enumerate}
+ \item Write down the additional terms $H_{kin}'$ of the kinetic part
+ of the Hamiltonian.
+ \item Chose a reasonable vector potential ${\bf A}$ to get a constant
+ magnetic field ${\bf B}$ in $z$-direction.
+ \item Rewrite the Hamiltonian
+ using the definition of the angular momentum operator
+ $L_z=x\frac{\partial}{\partial y}-y\frac{\partial}{\partial x}$.
+ \item Calculate the magnetic suscebtibility in a state $\phi$.
+ What term is responsible for the diamagnetic contribution?
+ {\bf Hint:} The magnetic suscebtibility is defined as
+ $\chi=-\frac{1}{V}\frac{\partial^2 E}{\partial B^2}$.
+ \item Assuming a spherically symmetric charge distribution the equality
+ $<\phi|x^2|\phi>=<\phi|y^2|\phi>=\frac{1}{3}<\phi|r^2|\phi>$
+ is valid. Rewrite the diamagnetic part of the suscebtibility
+ and compare the result to the one obtained
+ by the classical approach.
+ \end{enumerate}
+\end{enumerate}
+
+\end{document}