From: hackbard <hackbard@sage.physik.uni-augsburg.de>
Date: Mon, 23 Jun 2008 13:12:44 +0000 (+0200)
Subject: fixed the tutorial
X-Git-Url: https://hackdaworld.org/cgi-bin/gitweb.cgi?a=commitdiff_plain;h=33ca95b143e3c667847d4edb2e0ffdd0ff4cd8c9;p=lectures%2Flatex.git

fixed the tutorial
---

diff --git a/solid_state_physics/tutorial/2_04.tex b/solid_state_physics/tutorial/2_04.tex
index abaf2c4..d974e5f 100644
--- a/solid_state_physics/tutorial/2_04.tex
+++ b/solid_state_physics/tutorial/2_04.tex
@@ -66,7 +66,7 @@
        Write down the total differential using the equalities
        $T=\left.\frac{\partial E}{\partial S}\right|_V$ and
        $-p=\left.\frac{\partial E}{\partial V}\right|_S$.
-       Use Legendre transformation to get the potentials
+       Apply Legendre transformation to the following potentials
        \begin{itemize}
         \item $H=E+pV$ (Enthalpy)
         \item $F=E-TS$ (Helmholtz free energy)
@@ -115,7 +115,7 @@ thermal expansion cannot be described by rigorously harmonic crystals.
        volume $V$, the coefficient of thermal expansion $\alpha_V$ and
        the inverse bulk modulus (isothermal compressibility)
        $\frac{1}{B}=-\frac{1}{V}\left.\frac{\partial V}{\partial p}\right|_T$.\\
-       $C_p=\left.\frac{\partial E}{\partial T}\right|_p$ is the heat capacity
+       $C_p=\left.\frac{\partial H}{\partial T}\right|_p$ is the heat capacity
        for constant pressure and
        $C_V=\left.\frac{\partial E}{\partial T}\right|_V$ is the heat capacity
        for constant volume.