X-Git-Url: https://hackdaworld.org/gitweb/?p=lectures%2Flatex.git;a=blobdiff_plain;f=physics_compact%2Fsolid.tex;h=5e69a799a18a5174921aabe05797cc83202675e6;hp=20ecfef44e2132a8f2f8eb73c9dd44480b5cf773;hb=6a26b9f5593acc0bf19241b2fe79f1acf51fb03e;hpb=a9f93985e52272cdecf902c4b559173a80f4b41d diff --git a/physics_compact/solid.tex b/physics_compact/solid.tex index 20ecfef..5e69a79 100644 --- a/physics_compact/solid.tex +++ b/physics_compact/solid.tex @@ -2,6 +2,10 @@ \chapter{Atomic structure} +\chapter{Reciprocal lattice} + +Example of primitive cell ... + \chapter{Electronic structure} \section{Noninteracting electrons} @@ -18,30 +22,441 @@ \subsubsection{Hohenberg-Kohn theorem} -Considering a system with a nondegenerate ground state, there is obviously only one ground-state charge density $n_0(\vec{r})$ that correpsonds to a given potential $V(\vec{r})$. +The Hamiltonian of a many-electron problem has the form +\begin{equation} +H=T+V+U\text{ ,} +\end{equation} +where +\begin{eqnarray} +T & = & \langle\Psi|\sum_{i=1}^N\frac{-\hbar^2}{2m}\nabla_i^2|\Psi\rangle\\ + & = & \frac{-\hbar^2}{2m} \sum_{i=1}^N \int d\vec{r} d\vec{r}' \, + \langle \Psi | \vec{r} \rangle \langle \vec{r} | + \nabla_i^2 + | \vec{r}' \rangle \langle \vec{r}' | \Psi \rangle\\ + & = & \frac{-\hbar^2}{2m} \sum_{i=1}^N \int d\vec{r} d\vec{r}' \, + \langle \Psi | \vec{r} \rangle \nabla_{\vec{r}_i} + \langle \vec{r} | \vec{r}' \rangle + \nabla_{\vec{r}'_i} \langle \vec{r}' | \Psi \rangle\\ + & = & \frac{-\hbar^2}{2m} \sum_{i=1}^N \int d\vec{r} d\vec{r}' \, + \nabla_{\vec{r}_i} \langle \Psi | \vec{r} \rangle + \delta_{\vec{r}\vec{r}'} + \nabla_{\vec{r}'_i} \langle \vec{r}' | \Psi \rangle\\ + & = & \frac{-\hbar^2}{2m} \sum_{i=1}^N \int d\vec{r} \, + \nabla_{\vec{r}_i} \Psi^*(\vec{r}) \nabla_{\vec{r}_i} \Psi(\vec{r}) + \text{ ,} \\ +V & = & \int V(\vec{r})\Psi^*(\vec{r})\Psi(\vec{r})d\vec{r} \text{ ,} \\ +U & = & \frac{1}{2}\int\frac{1}{\left|\vec{r}-\vec{r}'\right|} + \Psi^*(\vec{r})\Psi^*(\vec{r}')\Psi(\vec{r}')\Psi(\vec{r}) + d\vec{r}d\vec{r}' +\end{eqnarray} +represent the kinetic energy, the energy due to the external potential and the energy due to the mutual Coulomb repulsion. + +\begin{remark} +As can be seen from the above, two many-electron systems can only differ in the external potential and the number of electrons. +The number of electrons is determined by the electron density. +\begin{equation} +N=\int n(\vec{r})d\vec{r} +\end{equation} +Now, if the external potential is additionally determined by the electron density, the density completely determines the many-body problem. +\end{remark} + +Considering a system with a nondegenerate ground state, there is obviously only one ground-state charge density $n_0(\vec{r})$ that corresponds to a given potential $V(\vec{r})$. +\begin{equation} +n_0(\vec{r})=\int \Psi_0^*(\vec{r},\vec{r}_2,\vec{r}_3,\ldots,\vec{r}_N) + \Psi_0(\vec{r},\vec{r}_2,\vec{r}_3,\ldots,\vec{r}_N) + d\vec{r}_2d\vec{r}_3\ldots d\vec{r}_N +\end{equation} In 1964, Hohenberg and Kohn showed the opposite and far less obvious result \cite{hohenberg64}. + +\begin{theorem}[Hohenberg / Kohn] For a nondegenerate ground state, the ground-state charge density uniquely determines the external potential in which the electrons reside. -The proof presented by Hohenberg and Kohn proceeds by {\em reductio ad absurdum}. +\end{theorem} +\begin{proof} +The proof presented by Hohenberg and Kohn proceeds by {\em reductio ad absurdum}. Suppose two potentials $V_1$ and $V_2$ exist, which yield the same electron density $n(\vec{r})$. The corresponding Hamiltonians are denoted $H_1$ and $H_2$ with the respective ground-state wavefunctions $\Psi_1$ and $\Psi_2$ and eigenvalues $E_1$ and $E_2$. Then, due to the variational principle (see \ref{sec:var_meth}), one can write \begin{equation} -E_1=\langle \Psi_1 | H_1 | \Psi_1 \rangle < \langle \Psi_2 | H_1 | \Psi_2 \rangle +E_1=\langle \Psi_1 | H_1 | \Psi_1 \rangle < +\langle \Psi_2 | H_1 | \Psi_2 \rangle \text{ .} +\label{subsub:hk01} \end{equation} -Expressing $H_1$ by $H_2+H_1-H_2$ +Expressing $H_1$ by $H_2+H_1-H_2$, the last part of \eqref{subsub:hk01} can be rewritten: \begin{equation} \langle \Psi_2 | H_1 | \Psi_2 \rangle = \langle \Psi_2 | H_2 | \Psi_2 \rangle + \langle \Psi_2 | H_1 -H_2 | \Psi_2 \rangle \end{equation} -and the fact that the two Hamiltonians, which describe the same number of electrons, differ only in the potential +The two Hamiltonians, which describe the same number of electrons, differ only in the potential \begin{equation} H_1-H_2=V_1(\vec{r})-V_2(\vec{r}) \end{equation} -one obtains +and, thus \begin{equation} E_1