X-Git-Url: https://hackdaworld.org/gitweb/?p=lectures%2Flatex.git;a=blobdiff_plain;f=physics_compact%2Fsolid.tex;h=6c25ff1c84608c02a46928917a2ab996605ad382;hp=20ecfef44e2132a8f2f8eb73c9dd44480b5cf773;hb=f2dddd61b086ccbe46fa103d509903c3a426c034;hpb=a9f93985e52272cdecf902c4b559173a80f4b41d diff --git a/physics_compact/solid.tex b/physics_compact/solid.tex index 20ecfef..6c25ff1 100644 --- a/physics_compact/solid.tex +++ b/physics_compact/solid.tex @@ -18,7 +18,7 @@ \subsubsection{Hohenberg-Kohn theorem} -Considering a system with a nondegenerate ground state, there is obviously only one ground-state charge density $n_0(\vec{r})$ that correpsonds to a given potential $V(\vec{r})$. +Considering a system with a nondegenerate ground state, there is obviously only one ground-state charge density $n_0(\vec{r})$ that corresponds to a given potential $V(\vec{r})$. In 1964, Hohenberg and Kohn showed the opposite and far less obvious result \cite{hohenberg64}. For a nondegenerate ground state, the ground-state charge density uniquely determines the external potential in which the electrons reside. The proof presented by Hohenberg and Kohn proceeds by {\em reductio ad absurdum}. @@ -27,21 +27,33 @@ Suppose two potentials $V_1$ and $V_2$ exist, which yield the same electron dens The corresponding Hamiltonians are denoted $H_1$ and $H_2$ with the respective ground-state wavefunctions $\Psi_1$ and $\Psi_2$ and eigenvalues $E_1$ and $E_2$. Then, due to the variational principle (see \ref{sec:var_meth}), one can write \begin{equation} -E_1=\langle \Psi_1 | H_1 | \Psi_1 \rangle < \langle \Psi_2 | H_1 | \Psi_2 \rangle +E_1=\langle \Psi_1 | H_1 | \Psi_1 \rangle < +\langle \Psi_2 | H_1 | \Psi_2 \rangle \text{ .} +\label{subsub:hk01} \end{equation} -Expressing $H_1$ by $H_2+H_1-H_2$ +Expressing $H_1$ by $H_2+H_1-H_2$, the last part of \eqref{subsub:hk01} can be rewritten: \begin{equation} \langle \Psi_2 | H_1 | \Psi_2 \rangle = \langle \Psi_2 | H_2 | \Psi_2 \rangle + \langle \Psi_2 | H_1 -H_2 | \Psi_2 \rangle \end{equation} -and the fact that the two Hamiltonians, which describe the same number of electrons, differ only in the potential +The two Hamiltonians, which describe the same number of electrons, differ only in the potential \begin{equation} H_1-H_2=V_1(\vec{r})-V_2(\vec{r}) \end{equation} -one obtains +and, thus \begin{equation} E_1