final

diff --git a/solid_state_physics/tutorial/2_02.tex b/solid_state_physics/tutorial/2_02.tex
index 5f280f0..8787db5 100644 (file)
--- a/solid_state_physics/tutorial/2_02.tex
+++ b/solid_state_physics/tutorial/2_02.tex
@@ -66,7 +66,7 @@ and $\lambda$ is the London penetration depth.
 \section{Penetration of the magnetic field into a type 1 superconductor}
 In the following, the behaviour of the magnetic field ${\bf B}_s({\bf r})$
 in the surface layer of a superconductor is calculated.
-In the superconductor the magnetic field is given by
+Inside the superconductor the magnetic field is given by
 \[
  {\bf B}_s=\mu_0 \left({\bf H}_a + {\bf M}_s\right)
 \]
@@ -82,7 +82,9 @@ ${\bf M}_s$ is the magnetization of the superconductor.
        magnetic field inside the superconductor?
        Apply the second London equation
        $\nabla \times {\bf j}_s=-{\bf B}_s/\Lambda$
+       with $\lambda=\sqrt{\Lambda/\mu_0}$
        relating the supercurrent to the magnetic field.
+       
  \item Consider a superconducting half space. The interface of the
        superconductor ($x>0$) and the vacuum ($x<0$) is located at $x=0$.
        A magnetic field ${\bf B}_a=\mu_0 H_a {\bf e}_z$
@@ -90,7 +92,7 @@ ${\bf M}_s$ is the magnetization of the superconductor.
        Calculate and sketch the decay of
        ${\bf B}_s=B_{s_z}(x) {\bf e}_x$
        in the superconductor.
-       Introduce the London penetration depth $\lambda=\sqrt{\Lambda/\mu_0}$.
+       Introduce the London penetration depth $\lambda$.
  \item Out of this, calculate the screening current density ${\bf j}_s$.
        What is the direction of the current?
        Calculate the value of ${\bf j}_s$ at the interface?