From 0d3acfac2b23ed5b37c86a77118a7f467f48c0e8 Mon Sep 17 00:00:00 2001 From: hackbard Date: Thu, 15 Sep 2011 12:29:15 +0200 Subject: [PATCH] average --- posic/thesis/basics.tex | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-) diff --git a/posic/thesis/basics.tex b/posic/thesis/basics.tex index bd2453e..249614a 100644 --- a/posic/thesis/basics.tex +++ b/posic/thesis/basics.tex @@ -566,7 +566,7 @@ Writing down the derivative of the total energy $E$ with respect to the position indeed reveals a contribution to the change in total energy due to the change of the wave functions $\Phi_j$. However, provided that the $\Phi_j$ are eigenstates of $H$, it is easy to show that the last two terms cancel each other and in the special case of $H=T+V$ the force is given by \begin{equation} -\vec{F}_i=-\sum_j \Phi_j^*\Phi_j\frac{\partial V}{\partial \vec{R}_i} +\vec{F}_i=-\sum_j \langle \Phi_j | \Phi_j\frac{\partial V}{\partial \vec{R}_i} \rangle \text{ .} \end{equation} This is called the Hellmann-Feynman theorem \cite{feynman39}, which enables the calculation of forces, called the Hellmann-Feynman forces, acting on the nuclei for a given configuration, without the need for evaluating computationally costly energy maps. -- 2.20.1