+In figure \ref{fig:defects:comb_db_05} c) and d) the nonparallel orientations, namely the \hkl<0 -1 0> and \hkl<1 0 0> dumbbells are shown.
+Binding energies of -1.88 eV and -1.38 eV are obtained for the relaxed structures.
+In both cases the silicon atom of the initial interstitial is pulled towards the near by atom of the second dumbbell so that both atoms form fourfold coordinated bonds to their next neighbours.
+In case c) it is the carbon and in case d) the silicon atom of the second interstitial to form the additional bond with the silicon atom of the initial interstitial.
+The atom of the second dumbbell, the carbon atom of the initial dumbbell and the two interconnecting silicon atoms again reside in a plane.
+A typical C-C distance of 2.79 \AA{} is, thus, observed for case c).
+The far-off atom of the second dumbbell resides in threefold coordination.
+
+Assuming that it is possible for the system to minimize free energy by reorientation of the dumbbell in any position ... we now give the minimum energies of dumbbells alomg the \hkl<1 1 0> direction ...
+\begin{table}[h]
+\begin{center}
+\begin{tabular}{l c c c c c c}
+\hline
+\hline
+ & 1 & 2 & 3 & 4 & 5 & 6\\
+\hline
+$E_{\text{b}}$ [eV] & -2.39 & -1.88 & -0.59 & -0.31 & - & - \\
+Type & \hkl<-1 0 0> & \hkl<1 0 0> & \hkl<1 0 0> & \hkl<1 0 0> & \hkl<> & \hkl<> \\
+\hline
+\hline
+\end{tabular}
+\end{center}
+\caption{Binding energy and type of the minimum energy configuration of an additional dumbbell with respect to the separation distance in bonds along the \hkl<1 1 0> direction.}
+\label{tab:defects:comb_db110}
+\end{table}