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getting more and more worth, rewrite?!?
author
hackbard
<hackbard@hackdaworld.org>
Sat, 11 Feb 2012 07:10:51 +0000
(08:10 +0100)
committer
hackbard
<hackbard@hackdaworld.org>
Sat, 11 Feb 2012 07:10:51 +0000
(08:10 +0100)
physics_compact/math.tex
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a/physics_compact/math.tex
b/physics_compact/math.tex
index
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57aef07
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--- a/
physics_compact/math.tex
+++ b/
physics_compact/math.tex
@@
-12,12
+12,12
@@
A vector $\vec{a}$ of an $N$-dimensional vector space (see \ref{math_app:vector_
\label{eq:vec_sum}
\end{equation}
i.e., if the basis set is complete, any vector can be written as a linear combination of these basis vectors.
\label{eq:vec_sum}
\end{equation}
i.e., if the basis set is complete, any vector can be written as a linear combination of these basis vectors.
-The scalar product
for an $N$-dimensional real
vector space is defined as
+The scalar product
in an $N$-dimensional Euclidean
vector space is defined as
\begin{equation}
(\vec{a},\vec{b})=\sum_i^N a_i b_i \text{ ,}
\label{eq:vec_sp}
\end{equation}
\begin{equation}
(\vec{a},\vec{b})=\sum_i^N a_i b_i \text{ ,}
\label{eq:vec_sp}
\end{equation}
-which enables to define a norm
+which
satisfies the properties of an inner product (see \ref{math_app:product}) and
enables to define a norm
\begin{equation}
||\vec{a}||=\sqrt{(\vec{a},\vec{a})}
\end{equation}
\begin{equation}
||\vec{a}||=\sqrt{(\vec{a},\vec{a})}
\end{equation}